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![]() Spring Semester 2007 |
num = raw_input("Enter the points: ") num = float(num) if (num >= 3.85): print "A" elif (num >= 3.5): print "A-" else: print "The rest is for you to complete."
Problem 15: the key is to import the random module and use the random.randrange(...) method.
Problem 16: range(...) produces a list of integers.
Here's an example of a list; for 5 times we select elements from it at random.
import random a = range(10) print a for i in range(5): j = random.randrange(len(a)) print a[j]
Interestingly enough this works for strings too:
import random a = "johnny english" print a for i in range(5): j = random.randrange(len(a)) print a[j]
Problem 18: the i-th multiple of 3 is 3 times i.
Problem 19: using an index, just as in the examples above (same for lists).
Problem 20: extremely simple, requires minor modifications to the "johnny english" example above.
Problem 21: print a[len(a)-1] + a[1:len(a)-1] + a[0].
This would be a perfect time to discuss negative indexing: a[-1] + a[1:-1] + a[0] works just as well.
Problem 22: there are two approaches to this problem, at least.
One simply uses the loop backwards from len(a)-1 to 0, one step at a time, and prints individual characters.
The other one reverses the string in the same manner by creating a new string, then printing that string.
Problem 23: a[1:]+a[0] is produced and stored in a at each iteration.
Problem 24: this the first circumstance where a while loop is needed.
bal = 10000 rat = 0.005 mon = 0 while bal >= 500 : mon += 1 bal = bal + rat * bal bal -= 500 print mon, bal print "This money will last", mon / 12, "year and", mon % 12, "months."
Problem 25: is for you to work out.
Problem 26: how much of this problem is solved by the following code?
import random secret = random.randrange(100) count = 0 guess = raw_input(str(count) + ". Enter your guess: ") while guess != str(secret): if guess == "show": print "I have chosen", secret else: count += 1 guess = raw_input(str(count) + ". Enter your guess: ")